dgitarist
Guest
письмо с аттачем
перЦЦы памагите вот такой код
function XMail($from, $to, $subj, $text, $filename)
{
$f = fopen($filename,"rb");
$un = strtoupper(uniqid(time()));
$head = "From: $from\n";
$head .= "To: $to\n";
$head .= "Subject: $subj\n";
$head .= "X-Mailer: PHPMail Tool\n";
$head .= "Reply-To: $from\n";
$head .= "Mime-Version: 1.0\n";
$head .= "Content-Type:multipart/mixed;";
$head .= "boundary=\"----------".$un."\"\n\n";
$zag = "------------".$un."\nContent-Type:text/html; charset=\"windows-1251\"; format=\"flowed\"\n";
$zag .= "Content-Transfer-Encoding: 8bit\n\n$text\n\n";
$zag .= "------------".$un."\n";
$zag .= "Content-Type: application/octet-stream;";
$zag .= "name=\"".basename($filename)."\"\n";
$zag .= "Content-Transfer-Encoding:base64\n";
$zag .= "Content-Disposition:attachment;";
$zag .= "filename=\"".basename($filename)."\"\n\n";
$zag .= chunk_split(base64_encode(fread($f,filesize($filename))))."\n";
if (!@mail("$to", "$subj", $zag, $head)) return 0; else return 1;
}
.......................
<input type='file' name='attach'>
..............................
XMail("....тута текст....","$v","..тут тоже........","..и тута тоже.......","$attach_"))
выдает такую ошибку
Warning: fopen(C:/phpdev/MYSQL README.txt): failed to open stream: No such file or directory in /home/churilo3/public_html/admin/2.php on line 4
Warning: filesize(): Stat failed for C:/phpdev/MYSQL README.txt (errno=2 - No such file or directory) in /home/churilo3/public_html/admin/2.php on line 22
Warning: fread(): supplied argument is not a valid stream resource in /home/churilo3/public_html/admin/2.php on line 22
письмо шлется но правда без содержимого файла
как сделать.
спасибо
перЦЦы памагите вот такой код
function XMail($from, $to, $subj, $text, $filename)
{
$f = fopen($filename,"rb");
$un = strtoupper(uniqid(time()));
$head = "From: $from\n";
$head .= "To: $to\n";
$head .= "Subject: $subj\n";
$head .= "X-Mailer: PHPMail Tool\n";
$head .= "Reply-To: $from\n";
$head .= "Mime-Version: 1.0\n";
$head .= "Content-Type:multipart/mixed;";
$head .= "boundary=\"----------".$un."\"\n\n";
$zag = "------------".$un."\nContent-Type:text/html; charset=\"windows-1251\"; format=\"flowed\"\n";
$zag .= "Content-Transfer-Encoding: 8bit\n\n$text\n\n";
$zag .= "------------".$un."\n";
$zag .= "Content-Type: application/octet-stream;";
$zag .= "name=\"".basename($filename)."\"\n";
$zag .= "Content-Transfer-Encoding:base64\n";
$zag .= "Content-Disposition:attachment;";
$zag .= "filename=\"".basename($filename)."\"\n\n";
$zag .= chunk_split(base64_encode(fread($f,filesize($filename))))."\n";
if (!@mail("$to", "$subj", $zag, $head)) return 0; else return 1;
}
.......................
<input type='file' name='attach'>
..............................
XMail("....тута текст....","$v","..тут тоже........","..и тута тоже.......","$attach_"))
выдает такую ошибку
Warning: fopen(C:/phpdev/MYSQL README.txt): failed to open stream: No such file or directory in /home/churilo3/public_html/admin/2.php on line 4
Warning: filesize(): Stat failed for C:/phpdev/MYSQL README.txt (errno=2 - No such file or directory) in /home/churilo3/public_html/admin/2.php on line 22
Warning: fread(): supplied argument is not a valid stream resource in /home/churilo3/public_html/admin/2.php on line 22
письмо шлется но правда без содержимого файла
как сделать.
спасибо